Question

Class 7 exponents and powers L-13
4) find the of m, if
a) 3^m = 729
b) 6^m *6^{2} = 1296

Answer 1

1)
${3}^{m} = {3}^{6} \\ m = 6$
2)

${6}^{m} \times {6}^{2} = 1296 \\ {6}^{m + 2} = {6}^{4} \\ m + 2 = 4 \\ m = 4 - 2 = 2$

Answer 2

hey bro!
here ur Ans!
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first we find factors of 729 & 1296

729= 3*3*3*3*3*3

1296= 2*2*2*2*3*3*3*3

now covert into same base digit

3^m = 3^6

when base is same take power value

m=6 Ans


b) 6^m* 6^2= (2*3)*(2*3)*(2*3)*(2*3)

6^m* 6^2= 6*6*6*6

now base is same take power value

m +2 =4

m = 4-2

m = 2 Ans

hope its helpful