class - 7
maths
in a triangle, ABC, if 2 angles A = 4 angles B = 6 angles C. calculate angle a, angle B and angle C
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By angle sum property:
∠A+∠B+∠C= 180°
Put the value of ∠A, ∠B, ∠C
X/2+x/4+x/6= 180°
L.c.m of 2,4,6 = 12
(6x + 3x +2x) /12 = 180°
11x = 12 × 180
X= (12× 180) /11
X= 196.36°
∠A= x/2
∠A= 196.36/2 = 98.18°
∠B= x/4
∠B= 196.36/4= 49.09°
∠C= x/6
∠C= 196.36/6 = 32.72°
_____________________________
Hence the angles be
∠A=98.18°
∠B=49.09°
∠C= 32.72°
∠A+∠B+∠C= 180°
Put the value of ∠A, ∠B, ∠C
X/2+x/4+x/6= 180°
L.c.m of 2,4,6 = 12
(6x + 3x +2x) /12 = 180°
11x = 12 × 180
X= (12× 180) /11
X= 196.36°
∠A= x/2
∠A= 196.36/2 = 98.18°
∠B= x/4
∠B= 196.36/4= 49.09°
∠C= x/6
∠C= 196.36/6 = 32.72°
_____________________________
Hence the angles be
∠A=98.18°
∠B=49.09°
∠C= 32.72°
learner2145:
He said ( 2 angles A) i.e A is divided by 2 but divided by 3.
In ∆ABC , 3∠A= 4∠B= 6∠C
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