Math, asked by kingitaat, 11 months ago

class - 7
maths
in a triangle, ABC, if 2 angles A = 4 angles B = 6 angles C. calculate angle a, angle B and angle C

Answers

Answered by akkassh
2
By angle sum property:

∠A+∠B+∠C= 180°

Put the value of ∠A, ∠B, ∠C

X/2+x/4+x/6= 180°

L.c.m of 2,4,6 = 12

(6x + 3x +2x) /12 = 180°

11x = 12 × 180

X= (12× 180) /11

X= 196.36°

∠A= x/2

∠A= 196.36/2 = 98.18°

∠B= x/4

∠B= 196.36/4= 49.09°

∠C= x/6

∠C= 196.36/6 = 32.72°

_____________________________

Hence the angles be

∠A=98.18°

∠B=49.09°

∠C= 32.72°

learner2145: He said ( 2 angles A) i.e A is divided by 2 but divided by 3.
akkassh: Given: 
In ∆ABC , 3∠A= 4∠B= 6∠C
akkassh: its given: Given: 3∠A= 4∠B= 6∠C
akkassh: ooops, i took it 3, but the question is saying 2... Sorry!
akkassh: Corrected!!
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