Question

Class 7 maths. Pls tell fast but correct. ​

Answer 1

$\large\fbox\red{Answer}$

$\dag\:\underline{\sf GiveN \::}$

• $\sf↦\:(\frac{2}{a})^{3} \times (\frac{2}{a}) ^{6}=(\frac{2}{a}) ^{2x-1}$

$\dag\:\underline{\sf SolutioN \::}$

$\sf↦\:(\frac{2}{a})^{3} \times (\frac{2}{a}) ^{6}=(\frac{2}{a}) ^{2x-1}$

We know,

$\tt\purple{a^{m} \times a^{n} = a^{m+n}}$

$\sf↦\:(\frac{2}{a})^{3+6}=(\frac{2}{a}) ^{2x-1}$

$\sf↦\:(\frac{2}{a})^{9}=(\frac{2}{a}) ^{2x-1}$

$\sf↦\:9=2x-1$

$\sf\:oR \:2x-1=9$

$\sf ↦\:2x=9+1$

$\sf↦\:2x=9+1$

$\sf↦\:2x=10$

$\sf↦\:x=\frac{10}{2}$

$\tt\pink{↦\:x=5}$

• Thnku :)

Answer 2

Answer

X is 5

Step-by-step explanation:

(2/9)^9

2*5=10

10-1=9