Question

class 7 maths question through a rectangular field of length 90m and 60m two roads are constructed which are parallel to the side and act each other at night angles through it centre of the fields if he width of each road is 3m​

Answer 1

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(i) Here, PQ = 3 m and PS = 60 m, EH

= 3 m and EF = 90 m and KL = 3 m and KN = 3 m Area of roads

= Area of PQRS + Area of EFGH – Area of KLMN

[∵ KLMN is taken twice, which is to besubtracted]

= PS x PQ + EF x EH – KL x KN

= (60 x 3) + (90 x 3) – (3 x 3)

= 180 + 270 – 9

= 441 m2

(ii) The cost of 1 m2 constructing the roads = Rs 110

The cost of 441 m2 constructing the roads

=Rs 110 x 441 =Rs 48,510

Therefore, the cost of constructing the roads = Rs 48,510