Class 7 Perimeter and Area
In a parallelogram, the altitude is twice the length of the base. If it's area sis 288sq.cm, find the base and altitude of the parallelogarm.
Answer is
base is 12cm
altitude is 24cm
But how, show steps
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Let the length of base, b be ' x '.
So according to the question,
Length of the altitude, h ( also known as height ) = 2x
Now,
We are given that the area of parallelogram is 288 sq. cm
Also we are aware of the formula of the area of a parallelogram,
Area of a parallelogram = b * h
So on relating both the equations,
b * h = 288 sq. cm
Substituting the values as we assumed,
x * 2x = 288
2x ^ 2 = 288
x ^ 2 = 288 / 2
x ^ 2 = 144
x = √ 144
x = 12 cm
Hence,
Base = x = 12 cm
Altitude = 2x = 2 * 12 = 24 cm
So according to the question,
Length of the altitude, h ( also known as height ) = 2x
Now,
We are given that the area of parallelogram is 288 sq. cm
Also we are aware of the formula of the area of a parallelogram,
Area of a parallelogram = b * h
So on relating both the equations,
b * h = 288 sq. cm
Substituting the values as we assumed,
x * 2x = 288
2x ^ 2 = 288
x ^ 2 = 288 / 2
x ^ 2 = 144
x = √ 144
x = 12 cm
Hence,
Base = x = 12 cm
Altitude = 2x = 2 * 12 = 24 cm
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