Class 7 (Perimeter)
Q1) Find the distance covered by Renu in taking 2 rounds of a rectangular park of length 65m and breath 40m .
Q2) Find the side of the regular pentagon whose perimeter is 120 cm.
Q3) The perimeter of a rectangular field is 236 m if it's length is 64 m .find it's breath.
Q4) If 336m of wire is required for fencing square Gardern. Find the side of the garder n.
Q5) Find the perimeter of a square whose side is 3x.
Q6) The length and breath of a rectangular field are 125m and 75m respectively. Find the cost of fencing it at the rated of RS 5 per metre.
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Q.1 -- Distance covered in 1 round of the rectangular field = 2 ( l+b ) = 2 ( 65 + 40 ) = 2 (105)
= 210 m
The distance covered in two rounds = 210 x 2 = 420 m.
Q.2 -- Perimeter of regular pentagon = 5a
120 = 5a
: a = 120/5
: a = 24 cm
Therefore, the side of the regular pentagon is 24 cm
Q.3 -- Let the breadth of rectangular field be 'b'
Perimeter of the rectangle = 2( l + b )
236 = 2 ( 64 + b)
236/2 = 64 + b
118 = 64 + b
b = 118 - 64
: b = 54
Therefore, the breadth of the rectangular field is 54 cm.
Q.4 -- Length of the wire to be fenced along a square field = 336 m.
We all know that the square has four equal sides.
Therefore, 336/4 = 82 m
Therefore, the side of the square field ( n ) is 82 m.
Q.5 -- Side of the square = 3x
Therefore, the perimeter of square = 3x x 4
= 12x cm
Q.6 -- Perimeter of the rectangular field = 2( 125+ 75) = 2( 200 ) = 400 m.
Therefore,cost of fencing the garden = 400 x 5
= 2000 m
Hope it helps you.......!
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