Math, asked by mdmustafa4556, 9 months ago

Class 7 (Perimeter)

Q1) Find the distance covered by Renu in taking 2 rounds of a rectangular park of length 65m and breath 40m .

Q2) Find the side of the regular pentagon whose perimeter is 120 cm.

Q3) The perimeter of a rectangular field is 236 m if it's length is 64 m .find it's breath.

Q4) If 336m of wire is required for fencing square Gardern. Find the side of the garder n.

Q5) Find the perimeter of a square whose side is 3x.

Q6) The length and breath of a rectangular field are 125m and 75m respectively. Find the cost of fencing it at the rated of RS 5 per metre.​

Answers

Answered by ShivamMallick
0

Answer:

1. 2(l+b)

2(65+40)

2(105)

215cm

He takes 2 rounds= 2×215

=430cm

3. 236m = 2(l+b)

236 = 2(64+b)

.....

Answered by jovinjsartho
1

Answer:

Q1) distance= 420cm

Q2) side= 24cm

Q3) breadth = 54 cm

Q4) side= 84 cm

Q5) perimeter= 12x

Q6) Cost= ₹2000

Step-by-step explanation:

Q1) Perimeter of rectangle =2(l+b)

l=65cm

b=40cm

Distance covered by Renu =2 (Perimeter of the rectangle

= 2(2(l+b))

=2(2(65+40))

=2(2(105)

=2(210)

=420cm

Q2) Perimeter =120 cm

side of pentagon = perimeter/5

=120/5

=24cm

Q3) Perimeter= 236cm

length =64cm

breadth =b

Perimeter=2(l+b)

236=2(64+b)

236/2= 64+b

118=64+b

118-64=b

54=b

Q4) side=m=336/4

side= m=84 cm

Q5) side= 3x

Perimeter= 4(side)

=4*3x

=12x

Q6) length= 125m

breadth= 75m

Perimeter= 2(l+b)

= 2(125+75)

=2*200

=400m

Cost of fencing 1m= ₹5

Cost of fencing = 400*₹5= ₹ 2000

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