Question

class 7 plz say full method ​

Answer 1

Answer:

Step-by-step explanation:

inΔADB & ΔADC

1-AB=AC  (given)

2-AD=AD  (common)

3-∠ABD=∠ACD ( opposite side of a triangle is equal)

∴ΔABD≅ΔADC BY SAS

plz mark as brainliest

Answer 2

Answer:

Given:

• D is the midpoint of BC.

Therefore, BD = CD. ...(i)

• AB = AC ...(ii)
• ∠ADB = ∠ADC ...(iii)

To prove: ∆ABD≅∆ADC

Proof:

(i) In ∆ABD and ∆ADC,

• BD = CD (S) ( from (i))
• AB = AC (S) ( from (ii))
• AD = AD (S) (Common Side)

Therefore, by SSS Conguency, ∆ABD≅∆ADC.

(ii) In ∆ABD and ∆ADC,

• BD = CD (S) ( from (i))
• AB = AC (A) ( from (ii))
• ∠ADB = ∠ADC (S) (from(iii))

Therefore, by SAS Conguency, ∆ABD≅∆ADC.

Hence, proved!