Question

Class 7 Rational Numbers

Answer 1

$i) \: additive \: inverse \: of \: \frac{5}{ - 7} = - 1( \frac{5}{ - 7}) = \frac{5}{7}$
$ii)additive \: inverse \: of \frac{6}{25} = - 1( \frac{6}{25} ) = \frac{ - 6}{25}$
$iii)additiv \: inverse \: of \frac{ - 16}{27 } = - 1( \frac{ - 16}{27} = \frac{16}{27}$
$additive \: inverse \: of \frac{ - 11}{ - 8} = - 1( \frac{ - 11}{ - 8}) = \frac{ - 11}{8}$
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Answer 2

i)additiveinverseof

−7

5

=−1(

−7

5

)=

7

5

ii)additive \: inverse \: of \frac{6}{25} = - 1( \frac{6}{25} ) = \frac{ - 6}{25}ii)additiveinverseof

25

6

=−1(

25

6

)=

25

−6

iii)additiv \: inverse \: of \frac{ - 16}{27 } = - 1( \frac{ - 16}{27} = \frac{16}{27}iii)additivinverseof

27

−16

=−1(

27

.−16

=

27

16

additive \: inverse \: of \frac{ - 11}{ - 8} = - 1( \frac{ - 11}{ - 8}) = \frac{ - 11}{8}additiveinverseof

−8

−11

=−1(

−8

−11

)=

8

−11

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