Question

class-7 word problem see from the photo and answers it fast and full solution class-7 ​

Answer 1

Answer:

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Step-by-step explanation:

An elevator descends into mine shaft at the rate of 6 meter per minute. So, for 1 min elevator descends 6 meters. The position of the elevator after one hour =

We know,

1 hour =60 min

60 min x 6 meters-360 meters.. But the elevator began to descend from 20 meters above.

So,

360 - 20= " 340 meters."

It's position after 45 mins = 45 meters x 6 mins = 270 meters.

The elevator has descended from 15 meters above So,

270-15 meters = 225 meters

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Answer 2

Answer:

Solution 7:

Starting position of mine shaft is = 10m above ground

but,

it moves in opposite direction so it travels the distance (-350 m ) below the ground.

Total distance covered by mine shaft = 10m - (-350m)

= 10 + 350

= 360m

Now, taken to cover a distance of 6m by it = 1 minute

Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min

6

1

min

Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \

6

1

× 360 = 60 min

60 minutes = 1 hour

thus, in one hour the mine shraft reaches = 350 below the ground