Question

class 7th
ch- perimeter and area plz tell the answer in full explanation I will mark brainst ​

Answer 1

EXPLANATION OF

QUESTION :

This question has provided you with the Length and Breadth (width) of a rectangular park, using these you're gonna find the length and breadth along with path by adding it's width twice, as it would appear twice in both length and breadth, using which you would be able to find the outer perimeter of the path.

Please refer to the attachment to understand what this question means using the diagram.

Now let's solve the question!

ANSWER

As Length of the rectangular park is 38cm, and the width of the Path is 3.5m,

L of Park with path = 38 + 3.5 + 3.5

$\bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$ = 45m

As Breadth/Width of the rectangular park is 15cm, and the width of the Path is 3.5m,

B of Park with path = 15 + 3.5 + 3.5

$\bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$ = 22m

Now,

P of park with path = 2(l + b)

$\bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:}$ = 2(45 + 22)

$\bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$ = 2 × 67

$\bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }$ = 134m

∴ The Outer Perimeter of the Path is 134m

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Hope this helps you! ♡

Answer 2

Step-by-step explanation:

Given:

Length of park = 38 m

Breadth of park = 15 m

width of constructed path = 3.5 m

According to the question,

The Length and breadth of park including the path constructed.

length = 38 + 3.5 + 3.5 = 45 m

breadth = 15 + 3.5 + 3.5 = 22 m

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To find:

the outer perimeter of the path

we have,

________________________________

Solution:

Perimeter of rectangle = 2 × (l + b)

i.e.

outer perimeter of the path

$= (2 \times (45 + 22) )\: m \\ = (2 \times 67) \: m \\ = 134 \: m$

Hence, the outer perimeter of the path is

134 m