Question

CLASS-8...
6. A sum of Rs.9600 is invested for 3 years
at 10% per annum compound interest.
Find the amount at the end of 3 years.​

Answer 1

Answer:

It is given that

Principal= 9600

Rate of interest = 10% p.a

Period = 3 years

We know that

Interest for the first year= Prt/100

Substituting the values

= (9600×10×1)/100

= 960

(i) Amount after one year = 9600 - 960= 10560

So the principal for the second year = 10560

Here the interest for the second year= (10560×10×1)/100

=1056

(ii) Amount after two years =10560+1056=11616

(iii) Compound interest earned in 2 years = 960+10560=2016

(iv) Difference between the answers in (ii) and (i) =11616−10560=1056

We know that

Interest on 1056 for 1 year at the rate of 10% p.a.= (1056×10×1)/100

=105.60

(v) Here

Principal for the third year = 11616

So the interest for the third year = (11616×10×1)/100

=1161.60

Answer 2

$\mathbb\pink{hey }$

$\mathbb\pink{here \: is \: ur \: answer}$

Given,

Principal=9600

Rate of interest=10%p.a

Period=3 years

We know that,

Interest for the first year=Prt/100

Substitution the values

=>(9600×10×1)/100

=>960

(i)Amount after one year=9600+960=10560

So,

The principal for the second year=10560

Here the interest for the Second year=(10560×10×1)/100

=1056

(ii)Amount after two years=10560+1056=11616

(iii)Compound interest earned in two years=960+10560=2016

(iv)Difference between the answer in(ii) and (i) =11616-10560=1056

We know that-

Interest on 1056 for 1 year at the rate of 10%p.a.=(1056×10×1)/100

=105.60

(v)Here

Principal for the third year=11616

So,the interest for the third year=(11616×10×1)/100

=1161.60