Question

class 8 chapter 13 exercise 13.1 q no. 9
A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long find at the same time (i) the lenght of the shadow cats by another pole 10 m 50 cm high (ii) the hight of a pole which casts a shadow 5m long ​

Answer 1

Answer :

8.75 meters.

Step-by-step explanation:

Let x m be the length of the pole whose shadow is of length 10m50cm.

Let y m be the length of the pole whose shadow is 5m long.

Clearly, it is a case of direct variation.

i)

3.20

5.60

=

x

10.50

x=

5.60

10.50×3.20

=6

Hence, the length of the shadow is 6m.

ii)

3.20

5.60

=

5

y

x=

3.20

5.60×5

=8.75

Hence, the length of the pole is 8.75 meters.