Question

Class 8 Find the Acceleration and Distance Travelled using Formula Find Acceleration if Initial Speed is 90 m/s and final is 180 m/s and time taken is 9 sec.

Answer 1

In this Case

Given

• Initial Velocity (u) = 90 m/s
• Final Velocity (v) = 180 m/s
• Time (t) = 9 s

To Find

• Acceleration (a)
• Distance Travelled (s)

Calculating Acceleration

Formula Used :- v = u + at

Substituting Values

☞ 180 = 90 + a × 9

☞ 180 = 90 + 9a

☞ 180 - 90 = 9a

☞ 90 = 9a

☞ 9a = 90

☞ a = 90/9

☞ a = 10

Therefore, we got Acceleration 10 m/s²

Calculating Distance Travelled

Formula Used :- v² - u² = 2as

Substituting Values

☞ (180)² - (90)² = 2 × 10 × s

☞ 32400 - 8100 = 20s

☞ 23400 = 20s

☞ 20s = 23400

☞ s = 23400/20

☞ s = 1170

Therefore, we got Distance Travelled 1170 m

Answer 2

Given :

• Acceleration : ?
• Initial speed : 180m/s
• Final speed : 90m/s
• Time : 9 sec.

TO Find :

Acceleration and distance .

Solution :

Acceleration :

• The rate of increase of speed .
• Formula :

$\small{\boxed{\sf{v = u + at}}}$

V - Initial velocity

U - Final velocity

T - Time

Putting up the values :

↝ 180 = 90 + 9a

↝ 9a = 180 - 90

↝ 9a = 90

↝ a = 90/9

a = 10m/s²

Distance :

$\small{\boxed{\sf{{v}^{2} - {u}^{2} = 2as}}}$

Putting up the values :

↝(180)² - (90)² = 2 × 10 × s

↝ 32400 - 8100 = 20s

↝23400 = 20s

↝s = 23400/20

So the distance traveled is 1170m

Supplementary information :

• Distance is the total unit of time travelled from the starting point to the ending point or the destination. It is usually measured in Km.

• Initial velocity is the velocity that is prevalent before the action of acceleration.

• Final velocity is the velocity or speed that is addition of initial velocity and acceleration.