class ,8 linear equation in one variable
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(2x-1)/3 – (6x-2)/5 = 1/3
By taking LCM for 3 and 5 which is 15,
[(2x-1)×5]/15 – [(6x-2)×3]/15 = 1/3
(10x – 5)/15 – (18x – 6)/15 = 1/3
(10x – 5 – 18x + 6)/15 = 1/3
(-8x + 1)/15 = 1/3
By using cross-multiplication we get,
(-8x + 1)3 = 15
-24x + 3 = 15
-24x = 15 – 3
-24x = 12
x = -12/24
= -1/2
therefore, x= -1/2
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