Question

class 8 math 2.2 q. 14
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Answer 1

Solution:

Let one number be x

Other number = x + 15

As per the condition of the question, we get

x + (x + 15) = 95

⇒ x + x + 15 = 95

⇒ 2x + 15 = 95

⇒ 2x = 95 – 15 [transposing 15 from (+) to (-)]

⇒ 2x = 80

⇒ x = [latex]\frac { 80 }{ 2 }[/latex] [transposing 2 from (×) to (÷)]

⇒ x = 40

Other number = 95 – 40 = 55

Thus, the required numbers are 40 and 55.

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