class 8 mathematics chapter 3 quadrilateral
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every quadrilateral has 360 sum of all angle
then
AOB +OBP+BPA+PAO = 360
90+90+35+BPA=360
115+BPA=360
BPA= 360-115
=145
plz add this ans for brenlylist
then
AOB +OBP+BPA+PAO = 360
90+90+35+BPA=360
115+BPA=360
BPA= 360-115
=145
plz add this ans for brenlylist
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