Math, asked by subbi22, 1 year ago

class 8 mathematics chapter 3 quadrilateral​

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Answered by sohamnarule
1
every quadrilateral has 360 sum of all angle

then

AOB +OBP+BPA+PAO = 360

90+90+35+BPA=360

115+BPA=360

BPA= 360-115

=145




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