*CLASS 8*
MATHS
CHAPTER 7
"CUBE AND CUBE ROOTS"
Find the cube root of each of the following numbers by prime factorisation method.
1) 216
3) 1000
2) 512
6) 91125
PLEASE GIVE CORRECT ANSWERS AND USE PRIME FACTORIZATION METHOD. I WILL MARK BRAINLIEST.
Answers
(1.) 216
√216 = √2*2*2*3*3*3
Now making groups of three's = 2*2*2 * 3*3*3
√216 = 2*3 = 6
(2.) 1000
√1000 = √2*2*2 * 5*5*5
√1000 = 2*5 = 10
(3.) 512
√512 = √2*2*2 * 2*2*2 * 2*2*2
√512 = 2*2*2 = 8
(4.) 91125
√91125 = √3*3*3 * 3*3*3 * 5*5*5
√91125 = 3*3*5 = 45
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Answer: so cube root of 216 =6
Cube root of 1000=10
Cube root of 512 =8
Cube root of 91125 = 45
Step-by-step explanation:
I ahve done for 216 and 512. I hope u could dp other two. Remember a thing while finding out the cube root make triplets means in 216 if we factorize =2×2×2×3×3×3 so there is a triplet 2 and so takea single three and a single two out of the root and multiply
As 2×3=6
I hpe it helps!
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