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NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.1
NCERT Solutions for Class 8 Maths Chapter 11, Mensuration, consist of a set of questions and answers for all the textbook problems. All the solutions are prepared by BYJU’S experts based on the latest CBSE syllabus and guidelines. The main aim is to give students the advantage of quality NCERT Solutions and a kick-start to their education. Our goal is to bring out the very best in students through additional skill-building exercises that are tailored to their grade levels, abilities and interests. Download free NCERT Solutions for Maths Chapter 11 and start practising offline.
Download PDF of NCERT Solutions for Class 8 Maths Chapter 11 Mensuration Exercise 11.1
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Access Other Exercise Solutions of Class 8 Maths Chapter 11 Mensuration
Exercise 11.2 Solutions : 11 Questions (Long answers)
Exercise 11.3 Solutions : 10 Questions (2 Short answers, 8 Long answers)
Exercise 11.4 Solutions : 8 Questions (2 Short answers, 6 Long answers)
Access Answers to NCERT Class 8 Maths Chapter 11 Mensuration Exercise 11.1 Page number 171
1.A square and a rectangular field with measurements as given in the figure have the same perimeter. Which field has a larger area?
Ncert solution class 8 chapter 11-1
Solution:
Side of a square = 60 m (Given)
And the length of rectangular field, l = 80 m (Given)
According to question,
Perimeter of rectangular field = Perimeter of square field
2(l+b) = 4×Side (using formulas)
2(80+b) = 4×60
160+2b = 240
b = 40
Breadth of the rectangle is 40 m.
Now, Area of Square field
= (side)2
= (60)2 = 3600 m2
And Area of Rectangular field
= length×breadth = 80×40
= 3200 m2
Hence, area of square field is larger.
2. Mrs.Kaushik has a square plot with the measurement as shown in the figure. She wants to construct a house in the middle of the plot. A garden is developed around the house. Find the total cost of developing a garden around the house at the rate of Rs. 55 per m2.
Ncert solution class 8 chapter 11-2
Solution:
Side of a square plot = 25 m
Formula: Area of square plot = square of a side = (side)2
= (25)2 = 625
Therefore the area of a square plot is 625 m2
Length of the house = 20 m and
Ncert solution class 8 chapter 11-3
Breadth of the house = 15 m
Area of the house = length×breadth
= 20×15 = 300 m2
Area of garden = Area of square plot – Area of house
= 625–300 = 325 m2
∵ Cost of developing the garden per sq. m is Rs. 55
Cost of developing the garden 325 sq. m = Rs. 55×325
= Rs. 17,875
Hence total cost of developing a garden around is Rs. 17,875.