Class 8 students or elderly, please help me with this question...!!!
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Step-by-step explanation:
3a(a+b+c) = 3a^2 + 3ab + 3ac
2b(a-b+c) = 2ab - 2b^2 + 2bc
4c(-a+b+c) = -4ac + 4bc + 4c^2
3a(a+b+c) - 2b(a-b+c) = 3a^2 + 3ab + 3ac - [2ab - 2b^2 + 2bc ]
= 3a^2 + 3ab + 3ac - 2ab + 2b^2 - 2bc
= 3a^2 + 2ab + 2b^2 - 3ac - 2bc
4c(-a+b+c) - [3a(a+b+c) - 2b(a-b+c) ]
= -4ac + 4bc + 4c^2 - [3a^2 + 2ab + 2b^2 - 3ac - 2bc]
= -4ac + 4bc + 4c^2 - 3a^2 - 2ab - 2b^2 + 3ac + 2bc
= -ac + 6bc + 4c^2 - 3a^2 - 2b^2
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