Math, asked by Anonymous, 6 months ago

Class:8

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✅✅Answer the question no,1,2,3,4,5,6✅✅

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Answers

Answered by Rohith11111
1

Answer:

you can do the 5th one it is similar to 4th one, you have to do LCM and count if each multiple is present 3 times or not.

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Answered by itzkaur93
1

Answer:

1 in pic

2. Solution:

area = a^2=8281

a= root (8281)

a= 91 m

Length of the side= 91 m

3 in pic

4.648 = 2 * 2 * 2 * 3 * 3 * 3 * 3

Hence the number should be multiplied by 3 * 3 = 9 to make it a perfect cube.

Now, new number = 648 * 9 = 5832

3√(5832) = 3√(2 * 2 * 2 * 3 * 3 * 3 * 3 * 3 * 3)

= 2 * 3 * 3

= 18

5.Here, the prime factors

11 is not present as triples.

Hence, we divide 704 by 11, so that the obtained number becomes a perfect cube.

704÷11=64=23×23=43 is a perfect cube.

Hence the smallest number by which

704 should be divided to make a perfect cube is 11.

Thanks dear

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