Question

CLASS - 9
1 The point whose abscissa is equal to its ordinate and which is equidistant from A(-1,0) and B (0,5) is
(a)(5,4)
(b)(2.2)
(-2,-2)
(d)(3.3)​

Answer 1

Answer:

Option(B)

Step-by-step explanation:

Let the point be C whose absicca = ordinate = a.

∴ C = (a,a)

Given, CA = CB

⇒ (a + 1)² + a² = a² + (a - 5)²

⇒ a² + 1 + a² + 2a = a² + a² + 25 - 10a

⇒ 12a = 24

⇒ a = 2

∴ The point is (2,2)

Hope it helps!

Answer 2

Let the point be (x, x) , so according to the condition (x+1)2 + (x –0)2 = (x –0)2 + (x –5)2 => x = 2