class 9 ...........
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which lesson can you mention please
answer is 8
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Let the point of intersection of BC and AD be O
In △ABO
⇒∠B<∠A
Thereore, ⇒AO<BO (1) (side opposite to greater angle is largest)
Similarly,
In △COD
⇒ ∠C<∠D
Thereore, ⇒DO<CO (2) (side opposite to greater angle is largest)
Adding (1) and (2) we get,
⇒ BO+OC>AO+DO
⇒ BC>AD
Step-by-step explanation:
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