Math, asked by singharun57045, 1 month ago

class 9 chapter 2 exercise 2.5 question number 3 with Answers​

Answers

Answered by jp087878
0

(i) We have, 9x2 + 6xy + y2

= (3x)2 + 2(3x)(y) + (y)2

= (3x + y)2

[Using a2 + 2ab + b2 = (a + b)2]

= (3x + y)(3x + y)

(ii) We have, 4y2 – 4y + 12

= (2y)2 + 2(2y)(1) + (1)2

= (2y -1)2

[Using a2 – 2ab + b2 = (a- b)2]

= (2y – 1)(2y – 1 )

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