Question

class 9
chapter 3 current electricity
science 1

consider a series combination of two resistors of resistance 10 ohm and 40 ohm across which a potential difference of 5V is applied. find the current in the circuit and the potential difference across each resistors​​

Answer 1

R eff=10+40=50 ohm
V=5V
I=v/R
=0.1 A

V in 10 ohm resistor

As it’s series i is same=0.1A
R=10 ohm
V=IR
V=1V

V in 40 ohm resistor
As series I constant =0.1 A
R=40 ohm
V=IR
V=4V

HERE V —->potential difference
I——->current
R——->resistance


Hope it helps