Question

ᴘʀᴏᴠᴇ ᴛʜᴀᴛ ᴀ ᴄʏᴄʟɪᴄ ᴘᴀʀᴀʟʟᴇʟᴏɢʀᴀᴍ ɪꜱ ᴀ ʀᴇᴄᴛᴀɴɢʟᴇ.



class-9
chapter-circles​

Answer 1

Step-by-step explanation:

ANSWER

Given,

ABCD is a cyclic parallelogram.

To prove,

ABCD is a rectangle.

Proof:

∠1+∠2=180° ...Opposite angles of a cyclic parallelogram

Also, Opposite angles of a cyclic parallelogram are equal.

Thus,

∠1=∠2

⇒∠1+∠1=180°

⇒∠1=90°

One of the interior angle of the parallelogram is right angled. Thus,

ABCD is a rectangle.

Answer 2

Step-by-step explanation:

• «1=90°
• 90°+90°=180°
• 45°+45°=90°