Question

class 9 chapter parallelogram exercise 2 level one ka ques no. 2
​

Answer 1

Answer:

please type question.

Answer 2

Answer:

Step-by-step explanation:

Q.2      If E, F, G and H are respectively the mid- points of the sides of a parallelogram ABCD, show that ar(EFGH) =12ar(ABCD)

Sol.        Δ HGF and || gm HDCF stand on the same base HF and lie between the same parallels HF and DC.  

8Therefore,   ar(ΔHGF) = 12ar(HDCF)          ... (1)  

Similarly, Δ HEF  and ||gm  ABFH stand on the same base HF and lie between the same parallels  

HF and AB.  

Therefore ar(ΔHEF) = 12ar(ABFH)          ... (2)  

Therefore Adding (1) and (2), we get  

ar(ΔHGF) + ar(ΔHEF) = 12ar(HDCF) + ar(ABFH)

⇒ ar(EFGH) = 12ar(ABCD)

HOPE ITS HELP YOU PLEASE MAKE ME BRAINLIEST