Math, asked by Mantsha4305, 8 months ago

class 9 contains 576 students. class 10 contains 448 students. find the maximum number of sections of both classes that are possible with same number of students in them.

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Answered by shradhakapoor2
20

Answer:

BRAINLEST!!

The total numbers of sections are 16.

Step-by-step explanation:

Given:

Number of boys in school = 576

Number of girls in school = 448

To find: Total Number of sections such that each section has either boys or girls.

Height Common Factor ( HCF ) of both number gives the number of students in a section.

HCF of 576 and 448

576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3

448 = 2 × 2 × 2 × 2 × 2 × 2 × 7

HCF = 2 × 2 × 2 × 2 × 2 × 2 = 64

Number of sections of Boys = 576/64 = 9

Number of sections of girls 448/64 = 7

Total Number of sections = 9 + 7 = 16

Therefore, The total numbers of sections are 16.

Answered by sonuvuce
16

The maximum number of sections of both classes that are possible with same number of students in them is 16

Step-by-step explanation:

Given

Class 9 has 576 students and class 10 has 448 students

To find out

The maximum no. of sections of both classes that are possible with same number of students in them

Solution:

Here we need to find the HCF of 576 and 448

From Euclid's division algorithm

576 = 448 × 1 + 128

Again

448 = 128 × 3 + 64

128 = 64 × 2 + 0

Therefore, HCF of 576 and 448 is 64

Thus, each sections will have 64 students

Now maximum number of sections that are possible

= (576/64) + (448/64)

= 9 + 7

= 16

Hope this answer is helpful.

Know More:

Q: There are 576 boys and 448 girls in a school that are to be divided into equal sections of either boys or girls alone. Find the total numbers of sections thus formed.

Click Here: https://brainly.in/question/4553628

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