Question

class 9
Derive the third equation of motion?​

Answer 1

Third equation of motion -:

=> Distance travelled = Average Velocity × Time

=> Distance travelled =InitialVelocity+FinalVelocity2×Time

=> s= v+u2×t

From equation (i) => v=u+at

or t=v−ua

∴ s= u+v2×v−ua = v²−u²2a

or v²-u² = 2as

or v²= u²+2as ——————(iii)

Where ,

u =initial velocity

v=final velocity

t= time

s= distance