Question

class 9 exercise 2.4 (problems 1(i,ii,iii) ​

Answer 1

Step-by-step explanation:

x3 – x2 – x + 1

Solution:

f(- 1) = (- 1)3 – (- 1)2 – (- 1) + 1

= -1 – 1 + 1 + 1 = 0

∴ (x + 1) is a factor.

ii) x4 -x3 +x2 – x + 1

Solution:

f(- 1) = (- 1)4 – (- 1)3 + (- 1)2 – (- 1) + 1

= 1 + 1 + 1 + 1 + 1= 5

∴ (x + 1) is not a factor.

iii) x4 + 2x3 + 2x2 + x + 1

Solution:

f(- 1) = (-1)4 + 2 (- 1)3 + 2 (- 1)2 + (-1) + 1

= 1 – 2 + 2 – 1 + 1 = 1

∴ (x + 1) is not a factor.