Question

Class 9 Math Chapter 1 Exercise-1.3 question 6 solve it please ​

Answer 1

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Answer 2

Answer:

/2 = 0. 5, denominator q = 21

7/8 = 0. 875, denominator q =23

4/5 = 0. 8, denominator q = 51

So, we conclude that terminating decimal may be obtained in the situation where prime factorization of the denominator of the given fractions has the power of only 2 or only 5 or both.

In the form of 2m × 5n, where n, m are natural numbers.