Question

class 9 maths chapter 1 exercise 1.6 question 2​

Answer 1

Step-by-step explanation:

✠ Answer \maltese✠

Given:

⇒ Initial Velocity (u) = 2.5 m/s

⇒ Acceleration (a) = 0.50 m/s²

⇒ Time (t) = 2 seconds

To Find:

The Distance (S) travelled by it in the first two second

Solution:

We know that,

\red{\underline{\large{\rm {Equation \ of \ Motion}}}}

Equation of Motion

\green{\boxed{\boxed{\rm S=ut+\dfrac{1}{2}at^{2}}}}

S=ut+

2

1

at

2

According to the Question,

We are asked to find the Distance (S) travelled by it in the first two second along the positive x-direction.

So, Using the Formula,

Given that,

u = 2.5 m/s

a = 0.50 m/s²

t = 2 seconds

Therefore,

Substituting the above values in the Formula,

We get,

\orange{\rm \implies S=(2.5)(2)+\dfrac{1}{2} (0.50)(2)^{2} \ \ m}⟹S=(2.5)(2)+

2

1

(0.50)(2)

2

m

\blue{\rm \implies S=5+\dfrac{1}{2} (0.50)(4) \ \ m}⟹S=5+

2

1

(0.50)(4) m

\green{\rm \implies S=5+\dfrac{1}{2}(2) \ \ m}⟹S=5+

2

1

(2) m

\orange{\rm \implies S=5+1 \ \ m}⟹S=5+1 m

\pink{\rm \implies S=6 \ \ m}⟹S=6 m

\red{\large{\boxed{\boxed{\rm Distance \ Travelled \; (S)=6 \ m}}}}

Distance Travelled(S)=6 m

Hence,

The Distance (S) travelled in the first two second = 6 m

Distance (S) = 6 m

Answer 2

Step-by-step explanation:

here is your answer

hope this will help you