Question

Class 9 Maths Chapter Lines And Angles​

Answer 1

Answer:

125

180-<A

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Answer 2

Ans

125°

Step-by-step explanation:

given <c=70° and ABC is isosceles triangle

let <CAB=x=<ABC

therefore <CAB+<CBA+<ABC =180°

x+x+70=180°

2x=110

x=55

therefore<CAB=<CBA=55°

as PQ and AB are parallel <A=<P

so <CPQ=55°

and <CPQ+<APQ=180°

55°+<APQ=180°

<APQ=125°