Question

Class 9 Maths Chapter: Polynomial

Find the value of k , if X- 1 is a factor of p(x) in each of the following cases :-
★ p(x)= kx²-3x+ k

Notice: Please don't answer if you don't know about it ​

Answer 1

Answer:

p(x) = kx² – 3x + k

Apply remainder theorem

=> x - 1 =0

=> x =  1

According to remainder theorem p(1) = 0 we get

Plug x = 1 we get  

P(1) = k(1)² -3(1) + k

0= k – 3 + k

0 = 2k – 3

3 = 2k

3/2 = k

k = 3/2

Answer 2

Answer:

If p(x)=$kx^{2} -3x+k$

and x-1 is a factor then,

x-1=0

x=1

Now replace x for 1-

p(x)=$K(1^{2} )-3(1)+k$

p(x)=k-3+k=0

2k-3=0

k=3/2

Step-by-step explanation:

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