Question

class 9 ncert chapter 9 question 9 pg 113

Answer 1

Answer:

construction : join AC AND PQ .

ar∆ACQ = ar∆APQ (between same parallel AQ and same base AQ)

subtract ar∆ABQ both sides

ar∆ACQ - ar∆ABQ = ar∆APQ - ar∆ABQ

ar∆ABC = ar∆PBQ

Multiply by 2 both sides

2ar∆ABC = 2ar∆PBQ

ar(ABCD) = ar(PBQR) {Because diagonal of parallelogram divides it into two triangles equal in area}