Question

Class 9 NCERT Maths Chapter 9 Areas of Parallelograms and Triangles Exercise 9.3 Question no. 4&6 Solutions..

Answer 1

Here is your answer mate..

4• Given . ABC and DBC are two angles on the same base . Line segment is CD is bisected by AB at O.


To prove: (Area of triangle ABC) = (Area of triangle ABD)

Proof: Line segment CD is bisected by AB at O.
OC=OD
BO is median of triangle BCD and AO is a median of triangle ACD .
BO is a median of triangle BCD .

So, Area of triangle OBC = Area of triangle OBD........(1)

So, AO is a median of triangle ACD

So, Area of triangle OAC = Area of triangle OAD.......(2)


Adding (1) and (2) we get,

Area of triangle OBC + Area of triangle OAC = Area of triangle OBD + Area of triangle OAD

= Area of triangle ABC = Area of triangle ABD


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