class 9 ncert maths exercise 11.2 all solutions
Answers
Answer:
1. Construct a triangle ABC in which BC = 7cm, ∠B = 75° and AB+AC = 13 cm.
Construction Procedure:
The steps to draw the triangle of given measurement is as follows:
1. Draw a line segment of base BC = 7 cm
2. Measure and draw ∠B = 75° and draw the ray BX
3. Take a compass and measure AB+AC = 13 cm.
4. With B as centre and draw an arc at the point be D
5. Join DC
6. Now draw the perpendicular bisector of the line BD and the intersection point is taken as A.
7. Now join AC
8. Therefore, ABC is the required triangle.
Ncert solutions class 9 chapter 11-13
2. Construct a triangle ABC in which BC = 8cm, ∠B = 45° and AB–AC = 3.5 cm.
Construction Procedure:
The steps to draw the triangle of given measurement is as follows:
1. Draw a line segment of base BC = 8 cm
2. Measure and draw ∠B = 45° and draw the ray BX
3. Take a compass and measure AB-AC = 3.5 cm.
4. With B as centre and draw an arc at the point be D on the ray BX
5. Join DC
6. Now draw the perpendicular bisector of the line CD and the intersection point is taken as A.
7. Now join AC
8. Therefore, ABC is the required triangle.
Ncert solutions class 9 chapter 11-14
3. Construct a triangle PQR in which QR = 6cm, ∠Q = 60° and PR–PQ = 2cm.
Construction Procedure:
The steps to draw the triangle of given measurement is as follows:
1. Draw a line segment of base QR = 6 cm
2. Measure and draw ∠Q = 60° and let the ray be QX
3. Take a compass and measure PR–PQ = 2cm.
4. Since PR–PQ is negative, QD will below the line QR.
5. With Q as centre and draw an arc at the point be D on the ray QX
6. Join DR
7. Now draw the perpendicular bisector of the line DR and the intersection point is taken as P.
8. Now join PR
9. Therefore, PQR is the required triangle.
Ncert solutions class 9 chapter 11-15
4. Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY+YZ+ZX = 11 cm.
Construction Procedure:
The steps to draw the triangle of given measurement is as follows:
1. Draw a line segment AB which is equal to XY+YZ+ZX = 11 cm.
2. Make an angle ∠Y = 30° from the point A and the angle be∠LAB
3. Make an angle ∠Z = 90° from the point B and the angle be ∠MAB
4. Bisect ∠LAB and ∠MAB at the point X.
5. Now take the perpendicular bisector of the line XA and XB and the intersection point be Y and Z respectively.
6. Join XY and XZ
7. Therefore, XYZ is the required triangle
Ncert solutions class 9 chapter 11-16
5. Construct a right triangle whose base is 12cm and sum of its hypotenuse and other side is 18 cm.
Construction Procedure:
The steps to draw the triangle of given measurement is as follows:
1. Draw a line segment of base BC = 12 cm
2. Measure and draw ∠B = 90° and draw the ray BX
3. Take a compass and measure AB+AC = 18 cm.
4. With B as centre and draw an arc at the point be D on the ray BX
5. Join DC
6. Now draw the perpendicular bisector of the line CD and the intersection point is taken as A.
7. Now join AC
8. Therefore, ABC is the required triangle.
Ncert solutions class 9 chapter 11-17
Constructions Exercise 11.2 includes 5 practical questions that are based on the concept of geometrical shapes and their process of construction. These exercise questions are crucial from an examination perspective as it helps the students to understand and solve the various questions that might arise from the topic. It also helps students to realize a particular concept’s real-world applications and its significance. Discover various concepts such as a bisector, perpendicular bisector and more, only on NCERT Solutions For Class 9 Maths.