Question

class 9 polynomials
Factorize 3y⁴- 243

Answer 1

$3(y {}^{4} - 81) \\ 3(y {}^{2} - 9) \times (y {}^{2} + 9) \\ 3(y - 3) \times (y + 3) \times (y {}{2} + 9)$

Answer 2

3y⁴- 243

= 3(y⁴ - 81). (Since 3 are common in both the terms)

= 3{(y²)² - 9²}

= 3(y² + 9)(y² - 9)

= 3(y² + 3²)(y² - 3²)

=3(y²+3²)(y + 3)(y - 3)

So 3, (y²+3²), (y + 3) and (y - 3) are the factors of 3y⁴- 243.