Class 9.
Science
A Ball throws a ball vertically upwards and catches it back in 5 seconds . Find Maximum height attained by the ball ( take g =10ms–² ) .
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D = (a * t2) / 2 = 10 * 5 * 5 / 2 = 5 * 5 * 5 = 125m
(Here t = Time, D = Distance and a = Acceleration)
But it covered half the distance while going up, and the other half when coming down.
Therefore the Max height of the ball will be 125/2 = 62.5m
(Here t = Time, D = Distance and a = Acceleration)
But it covered half the distance while going up, and the other half when coming down.
Therefore the Max height of the ball will be 125/2 = 62.5m
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