Question

class 9 science chapter motion question​

Answer 1

Final velocity

v = u + at

u = 0 m/s, a = 2 m/s2

final velocity, v = 0 + 2x10 = 20 m/s

final velocity, v = 20 m/s

Distance travelled,

$s = ut + \frac{1}{2} a {t}^{2} \\ s = \frac{1}{2} a {t}^{2} \\ s = \frac{1}{2} \times 2 \times {10}^{2} \\ s = 100 \: meter$

$s = ut + \frac{1}{2} a {t}^{2} \\ s = \frac{1}{2} a {t}^{2} \\ s = \frac{1}{2} \times 2 \times {10}^{2} \\ s = 100 \: meter$Distance travelled = 100 meter

Answer 2

Answer: We know that if it starts from rest so,

CASE 1/PART 1

u=0m/s

t= 10 sec

v= ?

a= 2m/s^2

v= u+at

v= 0+2*10

v=20m/s

CASE 2/PART 2

s= ?

so by using 2as=v^2-u^2

2*2*s= 20^2-0^2

4s= 400

s= 400/4

s= 100m

Explanation: Never forget to write unit. Please mark me brainlist and I am  in class 9