Question

Class 9:-
There are some motorcycles and cars in a parking ground.The total number of vechicles is 21 and the total number of wheels is 60. Find the number of motorcycles and cars
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Answer 1

✬ Cars = 9 ✬

✬ Motorcycles = 12 ✬

Step-by-step explanation:

Given:

• Total number of vehicles in park is 21.
• Total number of wheels in park is 60.

To Find:

• What is the number of motorcycles and cars in park ?

Solution: Let number of cars be x and number of bikes be y. Therefore,

➟ Cars + Motorcycles = Total vehicles

➟ x + y = 21

➟ x = 21 – y ......(1)

Now,

• We know that cars have 4 wheels and bikes have 2.

Then,

➟ Car's wheel + Bike's wheels = Total wheels

➟ 4 $\times$ x + 2 $\times$ y = 60

➟ 4x + 2y = 60......(2)

[ Put the value of x in equation (2) from (1) ]

$\implies{\rm }$ 4(21 – y) + 2y = 60

$\implies{\rm }$ 84 – 4y + 2y = 60

$\implies{\rm }$ 84 – 2y = 60

$\implies{\rm }$ 84 – 60 = 2y

$\implies{\rm }$ 24 = 2y

$\implies{\rm }$ 24/2 = y

$\implies{\rm }$ 12 = y

Hence,

➙ Number of motorcycles = y = 12

➙ Number of cars = x = (21 – y)

=> (21 – 12)

=> 9

Answer 2

$\huge{\mathbb{\red{ANSWER}}}$

Cars = 9

Motorcycles = 12

Step-by-step explanation:

$\huge{\mathbb{\red{Given}}}$

Total number of vehicles in park is 21.

Total number of wheels in park is 60.

To Find:

What is the number of motorcycles and cars in park ?

Solution: Let number of cars be x and number of bikes be y. Therefore,

➟ Cars + Motorcycles = Total vehicles

➟ x + y = 21

➟ x = 21 – y ......(1)

$\huge{\mathbb{\red{Now}}}$

We know that cars have 4 wheels and bikes have 2.

Then,

➟ Car's wheel + Bike's wheels = Total wheels

➟ 4 \times× x + 2 \times× y = 60

➟ 4x + 2y = 60......(2)

[ Put the value of x in equation (2) from (1) ]

\implies{\rm }⟹ 4(21 – y) + 2y = 60

\implies{\rm }⟹ 84 – 4y + 2y = 60

\implies{\rm }⟹ 84 – 2y = 60

\implies{\rm }⟹ 84 – 60 = 2y

\implies{\rm }⟹ 24 = 2y

\implies{\rm }⟹ 24/2 = y

\implies{\rm }⟹ 12 = y

Hence,

➙ Number of motorcycles = y = 12

➙ Number of cars = x = (21 – y)

=> (21 – 12)

=> $\huge{\mathbb{\red{9.Cars}}}$