Question

class 9th answer please...​

Answer 1

this is the solution for your question

Answer 2

Answer:

1.(I)3

(ii)2

(iii)-3

2.(i)p(0)=1

p(1)=1

p(2)=3

(ii)p(0)=2

p(1)=4

p(2)=4

(iii)p(0)=0

p(1)=1

p(2)=8

(iv)p(0)=-1

p(1)=0

p(2)=3

Step-by-step explanation:

1.putting value of x simultaneously

(i)5(0)-4(0)^2+3=3

(ii)5(-1)-4(-1)^2+3=-5+4+3=2

(iii)5(2)-4(2)^2+3=10-16+3=-3

2.(i)p(y)=y^2-y+1

p(0)=0-0+1=1

p(1)=1-1+1=1

p(2)=(2)^2-2+1=4-2+1=3

(ii)p(t)=2+t+2t^2+t^3

p(0)=2+0+0+0=2

p(1)=2+1+2-1=4

p(2)=2+2+2(2)^2-(2)^3=4+8-8=4

(iii)p(x)=x^3

p(0)=0

p(1)=(1)^3=1

p(2)=(2)^3=8

(iv)p(x)=(x-1)(x+1)

p(0)=(0-1)(0+1)=-1

p(1)=(1-1)(1+1)=0*2=0

p(2)=(2-1)(2+1)=1*3=3