Question

class 9th


answer plz​

Answer 1

$\frac{1}{2+\sqrt{3}}$

Multiplying by $\frac{2-\sqrt{3}}{2-\sqrt{3}}$

$\frac{1 }{2+\sqrt{3}}\\=\frac{1 }{2+\sqrt{3}}\times\frac{2-\sqrt{3}}{2-\sqrt{3}}\\=\frac{2-\sqrt{3} }{(2+\sqrt{3})(2-\sqrt{3})}\\=\frac{2-\sqrt{3}}{2^2-(\sqrt{3})^2} \\=\frac{2-\sqrt{3}}{4-3}\\=\frac{2-\sqrt{3}}{1}\\=2-\sqrt{3}$