Question

class 9th


answer plz​

Answer 1

Answer:

Consider triangles ADC and ABC,

AD =AB

Sidesofarhombus

AC is common.

CD=CB

∴ΔADC≅ΔABC

⇒∠DAC=∠BAC …(i)

and ∠DCA=∠BCA (i˙)

Hence AC bisects ∠A and ∠C.

Similarly, by taking triangles BAD and BCD, we can show that BD bisects ∠B and ∠D