Question

class 9th mathematics chapter 4 exercise 4.1
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Answer 1

Question:-

• Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case :

• 2x + 3y = 9.35
• $x - \frac{y}{5} -10=0$

• -2x + 3y = 6

• x = 3y

• 2x = -5y

• 3x + 2 = 0

• y – 2 = 0

• 5 = 2x

Solution:-

1 ) We have 2x + 3y = 9.35

or (2)x + (3)y + (−9.35 ) = 0

Comparing it with ax + by +c= 0, we get a = 2,  b = 3 and c= –9.35.

2) We have  $x - \frac{y}{5} -10=0$  

or x + $(\frac{-1}{5} )y +(10)=0$

Comparing it with ax + by + c = 0, we get

a =1, b = $(-\frac{1}{5} )$ and c= -10

3) We have -2x + 3y = 6

or (-2)x+ (3)y + (-6) = 0

Comparing it with ax – 4 – by + c = 0,we get a = -2, b = 3 and c = -6.

4) We have x = 3y

or (1)x + (-3)y + (0) = 0

Comparing it with ax + by + c = 0, we get a = 1, b = -3 and c = 0.

5)We have 2x = -5y

or (2)x + (5)y + (0) = 0

Comparing it with ax + by + c = 0, we get a = 2, b = 5 and c = 0.

6)We have 3x + 2 = 0

or (3)x + (0)y + (2) = 0

Comparing it with ax + by + c = 0, we get a = 3, b = 0 and c = 2.

7)We have y – 2 = 0

or (0)x + (1)y + (-2) = 0

Comparing it with ax + by + c = 0, we get a = 0, b = 1 and c = -2.

8)We have 5 = 2x ⇒ 5 – 2x = 0

or -2x + 0y + 5 = 0

or (-2)x + (0)y + (5) = 0

Comparing it with ax + by + c = 0, we get a = -2, b = 0 and c = 5.