Question

Class 9th
Mathematics
Chapter 9 - Areas of parellogram and triangles
Formulas Needed . Give 1 example for each Formuals

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Answer 1

Answer:

Area of ΔADC = 1/2 x base DC x corresponding altitude AN

Area of ΔADC = 1/2 x base DC x corresponding altitude ANTRIANGLES ON THE SAME BASE AND BETWEEN THE SAME PARALLELS

Area of ΔADC = 1/2 x base DC x corresponding altitude ANTRIANGLES ON THE SAME BASE AND BETWEEN THE SAME PARALLELSIn other words, area of a triangle is half the product of its base (or any side) and the corresponding altitude (or height).

Area of ΔADC = 1/2 x base DC x corresponding altitude ANTRIANGLES ON THE SAME BASE AND BETWEEN THE SAME PARALLELSIn other words, area of a triangle is half the product of its base (or any side) and the corresponding altitude (or height).Remarks : Two triangles with same base (or equal bases) and equal areas will have equal corresponding altitudes.

Area of ΔADC = 1/2 x base DC x corresponding altitude ANTRIANGLES ON THE SAME BASE AND BETWEEN THE SAME PARALLELSIn other words, area of a triangle is half the product of its base (or any side) and the corresponding altitude (or height).Remarks : Two triangles with same base (or equal bases) and equal areas will have equal corresponding altitudes.Theorem : Two triangles having the same base (or equal bases) and equal areas lie between the same parallels.

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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Formula of a parallegram is :

$= > b \: \times h$

Example :

If base Is 10 cm and height is 2 cm

Answer:

$= > 10 \times 2$

$= > 20 {cm}^{2}$

Formula of a triangle=

$= > \frac{1}{2} \times b \times h$

Example=

If base is 15 cm and height is 4 cm.

Answer:

$= > \frac{1}{2} \times 15 \times 4$

$= > 15 \times 2$

$= > {30cm}^{2}$