Math, asked by Anonymous, 1 month ago

Class 9th
Mathematics
Chapter 9 - Areas of parellogram and triangles
Formulas Needed . Give 1 example for each Formuals

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Quality answer with good explanation will be Brainliest .​

Answers

Answered by jecquiline
6

Area of a parallelogram = b×h

Area of a triangle = (1/2)×b×h

Hope it helps (^-^)

Answered by sia1234567
7

 \green{\small\sf\underline{about \: some \:  plane \: figures - }}

 \bold{ \mapsto \: what \: are \: plain \: figures \:?}

  \star\sf{ \: plain \: figures \: are \: those \: figures \:which \: do \: not \: any \: thickness. }

 \bold{\mapsto \: examples \: of \: plain \: figures \: ? }

 \sf\star{ \: examples \: include - } \\  \leadsto \: square \\  \leadsto \: rectangle \\  \leadsto \: circle \\  \leadsto \: parallelogram \\ etc...

________________________________

\mapsto \:\bold{area \: of \: triangle \: ? }

  \leadsto \:  \sf{formulae}  \: \blacktriangledown

 \color{blue}1. \:  \sf{area \: of \:  \triangle =  \frac{1}{2} \: base \times height}

 \bold{example - } \\  \bigstar \:  \sf{find \: area \: of \: triangle  \: ?} \\   \bold{\star \: when \:  -  \: base  = 6  \: and \: height = 10}

 \sf\huge\green{answer}

  \pink{area =  \frac{1}{2} \times base \times height}  \\ \blue{\frac{1}{2}  \times 6 \times 10 =  {30 \: cm}^{2}}

 \color{blue}2. \: area \: of \: \triangle =  \sqrt{s(s - a)(s - b)(s - c)}  \\ where  - \\ \star \: a  \: \star\: b \: and  \star\: c \\ are \: the \: sides \: of \: the \: triangle \: and \: s \: is \: the \: semiperimeter \: of \: the \: triangle

\bold{\mapsto \: area \: of \: parallelogram \: ? }

 \leadsto \sf{formulae}  \: \blacktriangledown

 \color{blue}1.  \sf \: area \: of \: parallelogram = base \times height

 \bold{example - } \\  \bigstar \:  \sf \: find \: area \: of \: parallelogram \: ? \\   \bold{\star \: when  \: -  \:  base = 8 \: cm \: and \: height = 3 \: cm \:}

 \huge \sf\green{answer}

 \dagger \:  \pink{area = base \times height} \\   \blue{= 8 \times 3  =  {24 \: cm}^{2}}

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