class 9th multiply (root 3+root 2) and (2 root 5 + 7 root 3)
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0
80agnn8nhrehnmoodyjko9
Answered by
11
The given equation is :
\frac{7\sqrt{3}}{\sqrt{10}+\sqrt{3}}-\frac{2\sqrt{5}}{\sqrt{6}+\sqrt{5}}-\frac{3\sqrt{2}}{\sqrt{15}+3\sqrt{2}}
10
+
3
7
3
−
6
+
5
2
5
−
15
+3
2
3
2
Rationalizing this equation, we get
=\frac{7\sqrt{3}(\sqrt{10}-\sqrt{3})}{10-3}-\frac{2\sqrt{5}(\sqrt{6}-\sqrt{5})}{6-5}-\frac{3\sqrt{2}(\sqrt{15}-3\sqrt{2})}{15-18}
10−3
7
3
(
10
−
3
)
−
6−5
2
5
(
6
−
5
)
−
15−18
3
2
(
15
−3
2
)
=\sqrt{3}(\sqrt{10}-\sqrt{3})-2\sqrt{5}(\sqrt{6}-\sqrt{5})+\sqrt{2}(\sqrt{15}-3\sqrt{2})
3
(
10
−
3
)−2
5
(
6
−
5
)+
2
(
15
−3
2
)
=\sqrt{30}-3-2\sqrt{30}+10+\sqrt{30}-6
30
−3−2
30
+10+
30
−6
=11
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