Question

Class 9th physics

Laws of motion based question

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Answer 1

hope the answer is helpful

Answer 2

Explanation:

Initially,

Speed of engine, V1 = 2m/s

And speed of wagon is V2 =0

Finally,

Speed of engine and wagon is same = u

Then accordingly law of mimentum conservation,

=> m1v1 +m2v2 = m1u +m2 u

=> 10000×2 + 20000×0 = 10000×u +

20000×u

=> 20000 = 30000 u

=> u = 2/3 m/s

So, commonly velocity is 2/3 m/s