Question

class 9th question no 1 of ch circle ex 10.6​

Answer 1

Answer:

Consider the following above diagram

In ΔPOO’ and ΔQOO’

OP = OQ (Radius of circle 1)

O’P = O’Q (Radius of circle 2)

OO’ = OO’ (Common arm)

So, by SSS congruency, ΔPOO’ ≅ ΔQOO’

Thus, ∠OPO’ = ∠OQO’ (proved)

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